0=-16t^2+130t+10

Solution for 0=-16t^2+130t+10 equation:

0=-16t^2+130t+10

We move all terms to the left:

0-(-16t^2+130t+10)=0

We add all the numbers together, and all the variables

-(-16t^2+130t+10)=0

We get rid of parentheses

16t^2-130t-10=0

a = 16; b = -130; c = -10;
Δ = b2-4ac
Δ = -1302-4·16·(-10)
Δ = 17540
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{17540}=\sqrt{4*4385}=\sqrt{4}*\sqrt{4385}=2\sqrt{4385}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-130)-2\sqrt{4385}}{2*16}=\frac{130-2\sqrt{4385}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-130)+2\sqrt{4385}}{2*16}=\frac{130+2\sqrt{4385}}{32}
$